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Relative to $F_{eff}$

Again, from Eq. (30), assuming $F_{eff}$ and $B_{eff}$ are independent,

\frac{1}{Tcal} \frac{\partial Tcal}{\partial F_{eff}} =
...}} + \frac{1}{\frac{T_{cab}-T_{emi}}{T_{cab}-T_{atm}}-F_{eff}}
\end{displaymath} (44)

which is of the order of 1.4 for the numerical values in Eq. (31). The first term must be omitted if one assumes $B_s$ = $F_{eff}$, and in this case the derivative is of the order of 0.26.

Gildas manager 2018-03-19